# How many memory locations can 14 address bit access?

How many memory locations can 14 address bit access? Answer: 2 ^ 14 memory location can be addressed by 14 bit address line.

How many locations can be addressed by a memory chip? For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address 220 (1,048,576) memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 232 (4,294,967,296) locations, or a 4 GiB address space.

How many memory location can be accessed if we are having an bit address bus? For example, an 8-bit-byte-addressable machine with a 20-bit address bus (e.g. Intel 8086) can address 220 (1,048,576) memory locations, or one MiB of memory, while a 32-bit bus (e.g. Intel 80386) addresses 232 (4,294,967,296) locations, or a 4 GiB address space.

How many bits are in a memory location? One memory location stores 1 byte (8 bits). The basic storage unit for memory is 1 byte. If you need to store 4 bytes, and place the first byte at 0001, the last byte will be at 0004. That’s one byte at each of 0001, 0002, 0003, and 0004.

## How many memory locations can 14 address bit access? – Related Questions

### How many memory locations can be addressed by a microprocessor that uses 24 bit addressing?

How many memory locations can be addressed by a microprocessor that uses 24 bit addressing? Answer: Aroun 16 Kilo Bytes of memory locations can be addressed.

### How many memory locations are addressed using 18 address bits?

How many memory locations are addressed using 18 address bits? Explanation: For n address bits, the memory location will consist of 2n bits. Using 18 address bits, 218 = 262,144 (= 256 K) words are addressed.

### How many different memory locations can be accessed using 12 bits?

13.4.

Each memory location is one byte, while the address is 12-bit, with the capability to address up to 4096 locations.

### How many locations are addressed using 12 address bits?

12 binary digits, or 3 nibbles (a ‘tribble’), have 4096 (10000 octal, 1000 hexadecimal) distinct combinations. Hence, a microprocessor with 12-bit memory addresses can directly access 4096 words (4 Kw) of word-addressable memory.

### How many address locations can a 16-bit microprocessor with 8 bit data bus address?

You used it indirectly: the total amount of addressable memory is 2 ^ 16 * 8 bits. Since one byte = 8 bits, that’s 2 ^16 bytes, i.e. 65536 bytes, or 64 KiB.

### How many memory locations can a 32-bit computer have?

A 32-bit system can access 232 memory addresses, i.e 4 GB of RAM or physical memory ideally, it can access more than 4 GB of RAM also. A 64-bit system can access 264 memory addresses, i.e actually 18-Quintillion bytes of RAM. In short, any amount of memory greater than 4 GB can be easily handled by it.

### Where are memory addresses stored?

MAR, which is found inside the CPU, goes either to the RAM (random-access memory) or cache. The memory address register is half of a minimal interface between a microprogram and computer storage; the other half is a memory data register.

### How many address bits are needed to select all memory locations in the 14k 1 RAM?

Explanation: If your RAM is organized as 32 bit words, then you need 4096+16*2^4 or 4352 addresses, if for 64 bit words, 2048+16*2^4 or 2304 addresses. In a system each byte is addressed individually. There are 1024 bytes in one k byte.

### How many memory locations can the 8085 Access if it has a 20 bit address bus?

Address Bus − 8085 has 16-bit address bus while 8086 has 20-bit address bus. Memory − 8085 can access up to 64Kb, whereas 8086 can access up to 1 Mb of memory. Instruction − 8085 doesn’t have an instruction queue, whereas 8086 has an instruction queue.

### What is the maximum number of memory locations that can be addressed by a chip with 16 address pins?

And that limits the amount of memory that can be accessed. For example, with a 16-bit address register, the address bus has 16 bits to address RAM and ROM. With 16 bits, a maximum of 216 = 65,536 words can be addressed.

### How much memory can be attached to a processor with 13 address lines *?

The total memory capacity is 64Kb. So, let 4 numbers of 8Kb EPROM and 4 numbers of 8Kb RAM. Each 8kb memory requires 13 address lines.

### How many address lines are required for a 2K memory?

It is 2k in size. 11 address lines are needed to address all the addresses inside the EPROM. A similar calculation reveals that the 2K RAM also needs 11 address lines.

### How many address bits are required for a 1024 * 8 memory?

How many address bits are required for a 1024 * 8 memory? Or 1024*8 gives 8192, or 2^13. so 13 bits. If it ain’t a 1024 bits multiplied by 8 bits, or there are 1024 arrays of each size of 8 bit, then 1024 arrays, so 10 bits of addresses will do it.

### How many address bits are required to select a memory location in a memory of 64 KB?

Total memory = 64KB = 26210B; hence 16 bits will be required to represent a memory location. 8. Registers R1 and R2 contain data values 1800 and 3800 respectively in decimal, and the word length of the processor is 4 bytes.

### How many address bits are required to select the memory location in 8kb memory capacity?

You need log2(n) bits to address n bytes. For example, you can store 256 different values in an 8 bit number, so 8 bits can address 256 bytes. 210 = 1024, so you need 10 bits to address every byte in a kilobyte.

### What is a 32 bit address?

A 32-bit address is the address of a single byte. Thirty-two wires of the bus contain an address (there are many more bus wires for timing and control). Sometimes people talk about addresses like 0x2000, which looks like a pattern of just 16 bits. But this is just an abbreviation for the full 32-bit address.

### What is the maximum memory addressing capacity of 8086?

Address Bus − 8085 has 16-bit address bus while 8086 has 20-bit address bus. Memory − 8085 can access up to 64Kb, whereas 8086 can access up to 1 Mb of memory.

### How many numbers is 16 bits?

A 16-bit integer can store 216 (or 65,536) distinct values. In an unsigned representation, these values are the integers between 0 and 65,535; using two’s complement, possible values range from −32,768 to 32,767.

### How many storage locations are available when a memory device has 10 address lines?

Hence there will be 212 storage locations.

### What is the maximum memory 8088 can access?

The 8088 also has a 20-bit address bus, so it can also address 220 or 10, 48, 576 memory locations. 4) The Features of 8086 Microprocessor can generate 16-bit I/O address, hence it can access 216 = 65536 I/O ports. 5) The 8086 provides fourteen 16-bit registers.

### What is the maximum memory capacity that an 8 bit address line can manage?

These processors have 8-bit CPUs with 8-bit data and 16-bit addressing. The memory on these CPUs is addressable at the byte level. This leads to a memory addressable limit of 216 × 1 byte = 65,536 bytes or 64 kilobytes.